12.96+x^2=36

Solution for 12.96+x^2=36 equation:

12.96+x^2=36

We move all terms to the left:

12.96+x^2-(36)=0

We add all the numbers together, and all the variables

x^2-23.04=0

a = 1; b = 0; c = -23.04;
Δ = b2-4ac
Δ = 02-4·1·(-23.04)
Δ = 92.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{92.16}}{2*1}=\frac{0-\sqrt{92.16}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{92.16}}{2*1}=\frac{0+\sqrt{92.16}}{2}
=\frac{\sqrt{}}{2}
$